(y+[y-1])+(y-1)(y-1)=

Solution for (y+[y-1])+(y-1)(y-1)= equation:

Simplifying
(y + [y + -1]) + (y + -1)(y + -1) = 0

Reorder the terms:
(y + [-1 + y]) + (y + -1)(y + -1) = 0

Remove brackets around [-1 + y]
(y + -1 + y) + (y + -1)(y + -1) = 0

Reorder the terms:
(-1 + y + y) + (y + -1)(y + -1) = 0

Combine like terms: y + y = 2y
(-1 + 2y) + (y + -1)(y + -1) = 0

Remove parenthesis around (-1 + 2y)
-1 + 2y + (y + -1)(y + -1) = 0

Reorder the terms:
-1 + 2y + (-1 + y)(y + -1) = 0

Reorder the terms:
-1 + 2y + (-1 + y)(-1 + y) = 0

Multiply (-1 + y) * (-1 + y)
-1 + 2y + (-1(-1 + y) + y(-1 + y)) = 0
-1 + 2y + ((-1 * -1 + y * -1) + y(-1 + y)) = 0
-1 + 2y + ((1 + -1y) + y(-1 + y)) = 0
-1 + 2y + (1 + -1y + (-1 * y + y * y)) = 0
-1 + 2y + (1 + -1y + (-1y + y2)) = 0

Combine like terms: -1y + -1y = -2y
-1 + 2y + (1 + -2y + y2) = 0

Reorder the terms:
-1 + 1 + 2y + -2y + y2 = 0

Combine like terms: -1 + 1 = 0
0 + 2y + -2y + y2 = 0
2y + -2y + y2 = 0

Combine like terms: 2y + -2y = 0
0 + y2 = 0
y2 = 0

Solving
y2 = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Simplifying
y2 = 0

Take the square root of each side:
y = {0}